Question

Question 14 of 14
Find the difference between successive terms
of the series 7, 41/3,12/3
f
1
1
8/3
2
3/8
3
Insufficient data
4
None of the above​

Answer 1

Answer:

3/8 ...........

..

.....

Answer 2

4. The difference between successive terms of the series 7, 41/3,12/3 is None of the above.

Given,

7, 41/3,12/3

To find,

difference in successive terms = ?

Solution,

difference in 7 and $\frac{41}{3}$ = $\frac{41}{3} - 7 = \frac{41-21}{3} = \frac{20}{3}$

difference in $\frac{12}{3} - \frac{41}{3} = \frac{12-41}{3} = \frac{-29}{3}$.

Since, the difference in terms is not consistent and different, none of the options is correct.

Therefore, none of the options is correct.