Math, asked by sasuji, 1 year ago

Question: 15
If α and β are the zeroes of the quadratic polynomial f(x) = x2 – p(x + 1) – c, show that (α + 1)(β + 1) = 1 – c.

Answers

Answered by love6385
0

Given that alpha and beta are the roots of the quadratic equation f(x) = x^2-p(x+ 1)-c = x^2-px-p-c = x^2 -px-(p+c),

Answered by DeviIQueen
0

Solution:

Since, α and β are the zeroes of the quadratic polynomial

f(x) = x2 – p(x + 1)– c

Now,

Sum of the zeroes = α + β = p

Product of the zeroes = α × β = (- p – c)

So,

(α + 1)(β + 1)

= αβ + α + β + 1

= αβ + (α + β) + 1

= (− p – c) + p + 1

= 1 – c = RHS

So, LHS = RHS

Hence, proved.

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