Question

Question 15. On passing electricity through dilute H2SO4 solution the amount of substance liberated at the cathode and anode are in the ratio:
(a) 1 : 8
(b) 8 : 1
(c) 16 : 1
(d) 1 : 16

Answer 1

answer is 1:8 of the compound

Answer 2

Answer:

The answer is 8:1

Explanation:

I cannot give exact and most appropriate explanation but when you pass electricity through dilute H₂SO₄ Solution,

At cathode: Hydrogen is liberated

At anode: Oxygen is liberated

The equivalent weight of Hydrogen is 1 and that of Oxygen is 8 and there's also some direct relation (I've less knowledge in Electrochemistry sorry)

So that's why the amount deposited is 1:8

Have a nice day :)