Question

Question 15 solve it

Answer 1

Answer:

Option a

Step-by-step explanation:

$12 \times (x^4 + x^3 + x^2)\\and\\18 \times (x^4 - x)\\\\12 \times (x^4 + x^3 + x^2) \\= 2 \times 6x^2 \times (x^2 + x + 1)\\= 2 \times 6x \times x \times (x^2 + x + 1)\\\\= 2x \times 6x \times (x^2 + x + 1)and\\18 \times (x^4 - x) \\= 3 \times 6x \times (x^3 -1)\\= 3 \times 6x \times (x -1)(x^2 + x + 1)\\= 3 \times (x -1) \times 6x \times (x^2 + x + 1)\\\\now \:common \: factor = 6x \times (x^2 + x + 1) \\LCM = 2x \times 3 \times (x-1) \times 6x \times (x^2 + x + 1)$

$= 36x^2 \times (x-1) \times (x^2 + x +1)\\= 36x^2 \times (x^3 -1)\\option \: a$