Question 15
यदि शंकु की तिर्यक ऊँचाई 21 सेमी और आधार का व्यास 24
सेमी है। शंकु का कुल पृष्ठीय क्षेत्रफल
है। If
slant height of the cone is 21 cm and the diameter of
the base is 24 cm. The total surface area of cone is
1200.77 cm2
Answers
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Answer:
sanku ki tiryak unchaai=21cm
sanku ka vyaas = 24/2
= 12cm
sanku ka PRISHTHIYE Chetraphal = πr( l+r)
=
22/7x12(21+12)
= 22/7x12(33)
=22x12x33/7
=8712/7
=1244.57cm square
Step-by-step explanation:
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