Question

Question 16 01 30
The area of an isosceles triangle having base 4 cm and length of one of equal sides as 6 cm is​

Answer 1

Answer:

two equal sides are 6cm

base is 4 cm

area of an isosceles triangle is

$\frac{1}{4} b \sqrt{4a {}^{2} } - {b}^{2}$

here, a =6 cm

b=4 cm

$\frac{1}{4} (4) \sqrt{4 {(6)}^{2} } - {(4)}^{2}$

√4(36)-(16)

√144-16

√128

11.31cm^2

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Answer 2

Answer:

Answer:

two equal sides are 6cm

base is 4 cm

area of an isosceles triangle is

\frac{1}{4} b \sqrt{4a {}^{2} } - {b}^{2}

4

1

b

4a

2

−b

2

here, a =6 cm

b=4 cm

\frac{1}{4} (4) \sqrt{4 {(6)}^{2} } - {(4)}^{2}

4

1

(4)

4(6)

2

−(4)

2

√4(36)-(16)

√144-16

√128

11.31cm^2

hope it helps u

please mark my answer as a brain list