Question 17 A man starts repaying a loan as first installment of Rs. 100. If he increases the installment by Rs 5 every month, what amount he will pay in the 30th installment?
Class X1 - Maths -Sequences and Series Page 186
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Answered by
20
here,
first term ( a ) = first installment of loan = 100 Rs
common difference ( d ) = increase installment per month = 5 Rs
now,
Tn = a + (n -1)d { by formula }
T30 = 100 + (30 -1) × 5
= 100 + 29 × 5
= 100 + 145
= 245 Rs
hence, he will pay in the 30th installment = 245 Rs
first term ( a ) = first installment of loan = 100 Rs
common difference ( d ) = increase installment per month = 5 Rs
now,
Tn = a + (n -1)d { by formula }
T30 = 100 + (30 -1) × 5
= 100 + 29 × 5
= 100 + 145
= 245 Rs
hence, he will pay in the 30th installment = 245 Rs
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6
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