Question 17 Find the equation for the ellipse that satisfies the given conditions: Foci (±3, 0), a = 4
Class X1 - Maths -Conic Sections Page 255
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Answered by
0
concept : for foci( ±c, 0) where , c² = a² - b² , equation of ellipse will be of the form , x²/a² + y²/b² = 1
Given,
Foci ( ± 3 , 0) = ( ± c , 0)
hence, c = 3 and given a = 4
so, c² = a² - b²
3² = 4² - b²
3² - 4² = - b²
b² = 4² - 3² = 16 - 9 = 7
hence, equation of ellipse
x²/a² + y²/b² = 1
put a² = 16 , b² = 7
x²/16 + y²/7 = 1
Given,
Foci ( ± 3 , 0) = ( ± c , 0)
hence, c = 3 and given a = 4
so, c² = a² - b²
3² = 4² - b²
3² - 4² = - b²
b² = 4² - 3² = 16 - 9 = 7
hence, equation of ellipse
x²/a² + y²/b² = 1
put a² = 16 , b² = 7
x²/16 + y²/7 = 1
Answered by
1
Hii friend,
For ellipse
Focus (+_c,0)
:-c=3 a= 4
a²-b²= c².
16-b²= 9
b²=7
For ellipse,
x²/a²+y²/b²= 1
x²/16+y²/7=1
Hope this helps you a little!!
For ellipse
Focus (+_c,0)
:-c=3 a= 4
a²-b²= c².
16-b²= 9
b²=7
For ellipse,
x²/a²+y²/b²= 1
x²/16+y²/7=1
Hope this helps you a little!!
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