Question

Question 17 (or part)

Answer 1

Answer:

Hey!!!

Refer attachment

Hope it helps!!!!!!!

Answer 2

Answer:The hint for Q.17 2nd part is that

=(sec@-tan@)(sec@+tan@)=1

=sec@+tan@ = p

So by adding,

We get 2sec@= 1+p

Then u can find the value of

tan@= (p-1)/2

So tan@/sec@ = sin@ = (p-1)/p+1

Step-by-step explanation: