Chemistry, asked by nimrah24, 10 months ago

question 18 please. I'll mark the answer brainliest.

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Answers

Answered by Hritik1011

2

Answer:

Option 2

Explanation:

From eqn 1 Enthalpy of formation for H2O(g) =-51kcal

From eqn 2 Enthalpy of formation for H2O(l) = - 68.3kcal

Enthalpy of vaporisation = - 51-(-68.3) =17.3kcal./ mole

For 1 gm=. 17.3 / molar mass = 17.3/18= 0.961 kcal

Mark as brainlist

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