question 18 please. I'll mark the answer brainliest.
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Answer:
Option 2
Explanation:
From eqn 1 Enthalpy of formation for H2O(g) =-51kcal
From eqn 2 Enthalpy of formation for H2O(l) = - 68.3kcal
Enthalpy of vaporisation = - 51-(-68.3) =17.3kcal./ mole
For 1 gm=. 17.3 / molar mass = 17.3/18= 0.961 kcal
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