Question

Question 19. A stone is dropped down a deep well from rest. The well is 50 meter deep.
How long will it take to reach the bottom of the well?
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Answer 1

Answer:

As per the question,

Initial velocity of the stone, Vi=0, Depth of well, h=50 m

assuming g=9.8 m/s^2

h=Vi *t +(1/2)gt^2=0*t +(1/2)*9.8*t^2

9.8*t^2 =2*50

t^2 =100/9.8

t=$\sqrt{100/9.8}$ =3.194==3.2 second

If we take g=10

Then

t=$\sqrt{100/10}$ =$\sqrt{10}$ second =3.162==3.2 seconds

Explanation: