Question

# Question 19
CLASS 10th
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Answer 1

Answer:

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Step-by-step explanation:

Total no. of faces on the die =6

No. of faces having A on it =2

No. of faces having D on it =1

Therefore,

P(getting A)= No. of faces having A / Total no. of faces

= 2/6

= 1/3

P(getting D)= No. of faces having D / Total no. of faces

= 1/6

Answer 2

Step-by-step explanation:

Given that:-

Letters are on the top face of the die

=A,B,C,D,E,A

Total number of faces of on a die =6

Total number of possible outcomes=6

Total number of times letter A on its face =2

remaining letters are one time each

Let rolling a die is a random experiment and each letter comes is an event then,

Probability of an event= Total number of favourable outcomes/Total number of all possible outcomes

1) Probability of getting A on the top face of die= No. of Favourable outcomes to A/Total

number of all possible outcomes

=>n(A)=2/6

n(A)=1/3

2) Probability of getting D on the top face of the die

=No. of favourable outcome to D/Total number of all possible outcomes

n(D)=1/6