question 19 with detailed solution
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Rate of diffusion = Volume/Time
Rate of diffusion of SO2 = R1
R1 = 20L/1min = 20 L/min
Rate of diffusion of R2
R2 = V/0.5min = 2V
According to Graham's law
R1/R2 = √(M2/M1)
20/(2V) = √(32/64)
10/V = √(32)/8
V = 80/√32
V = 14.14L
Option (B) is correct
Rate of diffusion of SO2 = R1
R1 = 20L/1min = 20 L/min
Rate of diffusion of R2
R2 = V/0.5min = 2V
According to Graham's law
R1/R2 = √(M2/M1)
20/(2V) = √(32/64)
10/V = √(32)/8
V = 80/√32
V = 14.14L
Option (B) is correct
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