question 2 1st and 2nd both
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1) x ^5÷1/(x)-3=49
x^5÷x^3=49
x^(5-3)=49
x^2=49
x=\/49=7
2)11^4x × 11^-3=11×121^4
11^(4x-3)=11 × {(11)^2}^4
11^(4x-3) =11×11^8
11^(4x-3)=11^(1+8)
In exponents
4x-3=9
x=(9-3)/4=6/4=3/2
x^5÷x^3=49
x^(5-3)=49
x^2=49
x=\/49=7
2)11^4x × 11^-3=11×121^4
11^(4x-3)=11 × {(11)^2}^4
11^(4x-3) =11×11^8
11^(4x-3)=11^(1+8)
In exponents
4x-3=9
x=(9-3)/4=6/4=3/2
Answered by
1
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