Question 2
2.1. An MTN cellular-phone user notices that her cellular phone accounts for three consecutive months were significantly different. In May, her account was one and a half times more than her account in June. Her account in July was R 50 more than her account in June. In total, she spent R575 in cellular-phone accounts in the three months. What was her account for each month? (7 marks)
2.2. The sum of three consecutive odd numbers is 45. What are the numbers? (3 marks)
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Answer:
May = Rs 225
June = Rs 150
July = Rs 200
13 , 15 , 17
Step-by-step explanation:
Let say june month account = J
May month account = J + 1.5J = 2.5J
July month account = J + 50
may + june + july = rs 575
J + 2.5J + J + 50 = 575
=> 4.5J = 525
=> J = 525/4.5
=> J = 116.67
May month account = 2.5 × 116.67 = Rs 291.67
June month account = rs 116.67
July Month account = Rs 166.67
if we say may month = 1.5 J
then
1.5 J + J + J + 50 = 575
3.5J = 525
J = 150
May = Rs 225
June = Rs 150
July = Rs 200
Three consecutive odd numbers
2n+1 , 2n+3 , 2n+5
2n+1 + 2n+3 + 2n +5 = 45
=> 6n = 36
=> n = 6
13 , 15 , 17
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