Math, asked by godiraonemaano, 10 months ago

Question 2
2.1. An MTN cellular-phone user notices that her cellular phone accounts for three
consecutive months were significantly different. In May, her account was one and a half
times more than her account in June. Her account in July was R 50 more than her account in
June. In total, she spent R575 in cellular-phone accounts in the three months. What was her
account for each month? (7 marks)
2.2. The sum of three consecutive odd numbers is 45. What are the numbers? (3 marks)

Answers

Answered by amitnrw
1

Answer:

May Bill =Rs 291.67  June Bill = Rs 116.67  ,  July bill = Rs 166.67  

May bill = Rs 225  June Bill = Rs 150  ,  July bill =  Rs 200

13 , 15 , 17

Step-by-step explanation:

2.1  

Let say June month bill was = Rs J

May month bill was = J + (3/2)J = 5J/2 Rs

July month bill = J + 50 Rs

May + june + July bill = Rs 575

=> 5J/2  + J + J + 50 = 575

=> 9J/2  = 525

=> J = 116.67

May Bill =Rs 291.67  June Bill = Rs 116.67  ,  July bill = Rs 166.67  

Correct Question May bill is one & half time then bill in June

then

3J/2  + J + J + 50 = 575

=> 7J/2 = 525

=> J = 150

May bill = Rs 225  June Bill = Rs 150  ,  July bill =  Rs 200

2.2

Let say three consecutive odd numbers are

2n+1 , 2n+3 , 2n+5

2n+1 + 2n+3 +2n + 5 = 45

=> 6n = 36

=> n = 6

numbers are

13 , 15 , 17

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