Question

question 2,3 please solve fast it's important

Answer 1

IN ADB AND ADC
AB= AC
BD = DC( D IS MID POINT OF BC)
AD = AD

SO ADB~ADC

SO

<A/<A = <D/<D = <B/<c
1 = <b/<c
<b = <c

3) in ABD AND ABC

AC= BD
AD = BC
AB= AB

SO ADB ~ BCA

SO ABC ~ BAD

2) IS MEANINGFULLY WRITTEN

Answer 2

2. In triangle' s ABD and ADC
AB =AC (given )
BD = CD ( D is the mid point of BC )
AD = AD ( common )
hence , Triangle ABD is congruent to triangle ADC ( by sss rule )
and angle B = angle C ( opposite angles of equal sides r equal )

3. In triangle's ABC nd BAD ..
BD = AC ( given )
AD = BC ( given )
AB = AB ( common )
then , triangle ABC is congruent to triangle BAD ( by sss rule)
option (ii) is correct meaningfully ..
hope this will help uhh..
nd plzz mark as brainliest....