Question 2.53 The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.
Class XI Structure of Atom Page 68
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we know,
E = hc/λ
here, h = 6.626 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 256.7 nm = 2.567 × 10^-7 m
E = 6.626 × 10^-34 Js × 3 × 10^8 m/s/2.567 × 10^-7 m
= 7.74 × 10^-19 J/1.602 × 10^-19 J/eV
= 4.83 eV
E = 4.83 eV
now, potential gives the kinetic energy to electron.
K.E = e × 0.35V = 0.35 eV
so, work function = Energy - K.E
= 4.83 eV - 0.35 eV
= 4.48 eV
E = hc/λ
here, h = 6.626 × 10^-34 Js
c = 3 × 10^8 m/s
λ = 256.7 nm = 2.567 × 10^-7 m
E = 6.626 × 10^-34 Js × 3 × 10^8 m/s/2.567 × 10^-7 m
= 7.74 × 10^-19 J/1.602 × 10^-19 J/eV
= 4.83 eV
E = 4.83 eV
now, potential gives the kinetic energy to electron.
K.E = e × 0.35V = 0.35 eV
so, work function = Energy - K.E
= 4.83 eV - 0.35 eV
= 4.48 eV
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