Question

Question: 2
A body moving with an initial
velocity of 5 m/s accelerates a
2m/s2. Its velocity after 10
seconds is ....​

Answer 1

$\maltese$ Answer $\maltese$

$\checkmark$ Given:

⇒ Initial velocity ( u ) = 5 m/s

⇒ Acceleration ( a ) = 2 m/s²

⇒ Time ( t ) = 10 seconds

$\checkmark$ To Find:

⇒ Its velocity after 10  seconds

$\checkmark$ Solution:

Equation of Motion

$\orange{\boxed{\boxed{\sf v=u+at}}}$

Here,

u = Initial velocity

v = Final velocity

a = Acceleration

t = Time

According to the Question,

We are asked to find the

Final Velocity ( v ) after 10 sec

Given that,

→ u = 5 m/s

→ a = 2 m/s²

→ t = 10 seconds

Therefore,

Substituting the above values in the Formula

We get,

$\green{\sf \implies v=5+2(10) \ m/s}$

$\red{\sf \implies v=5+20 \ m/s}$

$\pink{\sf \implies v=25 \ m/s}$

Final Velocity (v) = 25 m/s

Hence,

The Velocity after 10 seconds is 25 m/s

Answer 2

✰ Given -

• Initial Velocity (u) = 5 m/s
• Acceleration (a) = 2 m/s²
• Time (t) = 10 sec

✰ To Find -

• Final Velocity (v) = ?

✰ Solution -

We know 1st Equation of Motion,

$✓ \: v = u + at$

Here,

• V = Final Velocity
• U = Initial Velocity
• A = Acceleration
• T = Time period

Placing Values,

$⟶ \: v = 5 + 2 \times (10)$

$⟶v = 5 + 20$

$⟶v = 25m/s$

⛬ Velocity after 10 sec is 25 m/s

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$✓ \: 3 \: </strong><strong>I</strong><strong>mp \: </strong><strong>E</strong><strong>quations \: </strong><strong>O</strong><strong>f</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>Motion-</strong><strong>$

1) $✓ \: v = u + at$

2) $✓ \: s = ut + \frac{1}{2} \: {at}^{2}$

3) $✓ \: {v}^{2} = {u}^{2} + 2as$

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