Question

Question 2 : A cyclist is to 200 m a circular bend of radius. The coefficient of friction between the
tyres and the road is 0.4.Calculate the maximum safe velocity for the cyclist.
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Answer 1

Answer:

Explanation:

The more the velocity the more the centrepetal force because:

centripetal force = $m\omega^{2}r$

Now the frictional force has to provide this cenrtipetal force :

$m\omega^{2}r$ = $mg\mu$

$\omega^{2} = \frac{\mu g}{r}\\\\\omega^{2} = \frac{0.4 \times 10}{200}\\\\\omega^{2} = 0.02 \\\\\frac{v^{2}}{r^{2}} = 0.02\\\\v^{2} = 0.02 \times 200 \times 200\\\\v^{2} = 800\\\\v = 20\sqrt{2}\\\\v = 20 \times 1.414\\\\v = 28.28 ms^{-1}$

This might help Thanks!