Question

Question-2: A force acts for 2 seconds on a body of mass 2 kg initially at rest. Just
after the force stops to act the body moves 10m in the next 2 seconds. Find the
magnitude of the force.​

Answer 1

THIS IS THE SOLUTION OF THE QUESTION ABOVE.

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Answer 2

Answer:

5/2N

Step-by-step explanation:

v=10/2=5

u=0.

t=4sec.

a=(v-u )/t.

a=(5-0)/4  =  5/4.

F=ma =5/2N