Question

Question 2
(a) In the figure A and B are the mid- points of two equal chords PQ and RS
respectively of a circle with center O. Prove that A0AQ = AOBS.​

Answer 1

Step-by-step explanation:

In given figure,

PQ=RS

A and B are mid-points of PQ and RS.

OA=OB

Because when two chords are equal then their distance from center are equal.

In triangle OAQ and OBS

OA=OB

PQ=RS

(PA=AQ,RB=BS)

(Radius of circle are equal)

OAQOBS

Reason: SSS postulate

Hence, proved.

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Answer 2

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