Question 2.
A spherical ball of mass 10-6 kg hits a wall
1000 times per second normally with a experienced by the wall is
velocity of 1000 m/s and rebounds with same
velocity along the initial direction. The force
(a) 1 N
(b) 4 N
(c) 2 N
(d) 8 N
Answers
Answered by
1
Answer:
c) 2N This is perfecta answer
Answered by
1
OPTION (C)
Step-by-step explanation:
ΔP = momentum
= mΔv
m = 10⁻⁶ kg
v = 1000 m/s
ΔP ball = mΔv
= 10⁻⁶ (-1000-1000)
= 10⁻⁶(-2000)
= -2× 10 ⁻³ kg m/s
ΔP wall = mΔv
= -( ΔP ball)
= 2× 10⁻³ kg m/s
ΔP = 2× 10⁻³ ×( number of times hitting)
= 2× 10³× 10⁻³
= 2 kg m/s
= 2 N
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