Question

Question 2 answer fast please it’s urgent

Answer 1

Hello!

AP = PB

⇒ AP² = PB²

⇒ (3 – 0)² + (k – 2)² = (k – 0)² + (5 – 2)²   

⇒ 9 + $\sf \cancel{k^{2}}$ – 4k + 4 = $\sf \cancel{k^{2}}$ + 9

⇒ – 4k + 4 = 0

⇒ 4k = 4

⇒ k = $\dfrac{4}{4}$ ⇒ $\bf{k=1}$

Cheers!

Answer 2

Answer:

ye to book vala answer h

Step-by-step explanation:

itna easy my god khud try karke dekho