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In a party of 77 people, there are twice as many women as children and twice as many children as men. How many men are present?
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Answer 1

Given :- In a party of 77 people, there are twice as many women as children and twice as many children as men. How many men are present ?

Solution :-

Let in party number of men were x .

so,

→ Number of children = Twice of men = 2x

and,

→ Number of women = Twice of children = 2 * 2x = 4x

then, A/q,

→ Number of men + Number of children + Number of women = Total people in party

→ x + 2x + 4x = 77

→ 7x = 77

→ x = 11 .

therefore, number of men present in the party were 11 .

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Answer 2

Given:

In a party of 77 people, there are twice as many women as children and twice as many children as men.

To find:

How many men are present?

Solution :

Total number of people = 77

There are twice as many children as men.

Let the number of men = x

So, the number of children = 2x

There are twice as many women as children.

So, the number of women = 2 (2x) = 4x

According to the question:

$= > x + 2x + 4x = 77$

$= > 7x = 77$

$= > x = \dfrac{77}{7}$

$= > x = 11$

Hence, the number of men = 11.