Question

Question 2
Calculate electrostatic potential energy stored in a system consisting of two point charges
100uC and 40u C separated by a distance of 9cm, in vacuum.

Answer 1

Explanation:

Given that,

First Charge q

1

=7μC

Second Charge q

2

=−2μC

Now, the distance

d=18cm

Now, the potential energy is

U=

4πε

0

1

×

r

q

1

q

2

U=9×10

9

×

0.18

−14×10

−12

U=−0.7J

Negative sign indicate that the interaction between the charges is attractive

Hence, the potential energy is 0.7 J