Question

Question 2. D and E are points on the sides AB
and AC respectively of a A ABC such that DE !
BC and divides a ABC into two parts, equal in
BD
area. Find
AB​

Answer 1

Answer:

We have,

Area(△ADE)=Area(trapeziumBCED)

⇒ Area(△ADE)+Area(△ADE)=Area(trapeziumBCED)+Area(△ADE)

⇒ 2Area(△ADE)=Area(△ABC)......(i)

In △ADE and △ABC, we have

∠ADE=∠B [∵DE∣∣BC∴∠ADE=∠B (Corresponding angles]

and, ∠A=∠A [Common]

∴ △ADE∼△ABC

Answer 2

Answer:

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Step-by-step explanation:

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