Question

Question 2

Evaluate:

Answer 1

Answer:

$\sqrt[3]{7} \sqrt{7} = {7}^{ \frac{1}{3} } \times {7}^{ \frac{1}{2} } = {7}^{ \frac{1}{3} + \frac{1}{2} } = {7}^{ \frac{5}{6} } \\ \sqrt[6]{ {7}^{5} } = {7}^{ \frac{5}{6} } \\ so \: \frac{ \sqrt[3]{7} \sqrt{7}}{ \sqrt[6]{ {7}^{5} } } = 1$