Math, asked by BrainlyHelper, 1 year ago

"Question 2 Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b, c in each case: (i)2x+3y=9.35 (ii) x-y/5-10=0(iii) − 2x + 3 y = 6 (iv) x = 3y (v) 2x = − 5y (vi) 3x + 2 = 0 (vii) y − 2 = 0 (viii) 5 = 2x

Class 9 - Math - Linear Equations in Two Variables Page 68"

Answers

Answered by nikitasingh79
531

An equation which can be put in the form ax+by+c=0, where a, b & c are real numbers x, y are variables, is called linear equation in two variables.

 

In equation ax+by+c=0, the values of x and y are always real.

·ax+by+c=0 is also called standard form a linear equation in two variables.


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Solution:

(i) 2x + 3y =9.35

2x + 3y -9.35 = 0

On comparing it to ax + by + c , We get:

a= 2, b=3  & c = -9.35

 

(ii) x  – y/5 -10=0

On comparing it to ax + by +c = 0

a =1, b= -1/5 & c = -10

 

(iii) -2x+3y = 6

-2x+3y-6=0

On comparing it to ax + by + c =0

a = -2, b = 3 and c = -6.

 

(iv) x =3y

x-3y+0=0

On comparing it to ax + by +c =0

a=1, b=-3 and c =0

 

(v) 2x= -5y

=2x + 5y – 0 = 0

a=2, b = 5 and c =0

 

(vi) 3x+2 =0

3x+0y+2=0

On comparing it to ax + by + c = 0

a=3, b=0 and c =2

 

vii) y-2=0

0x+y-2=0

 

On comparing it to ax + by + c = 0

a=0, b=1, c =-2

 

viii) 5=2x

-2x+0y+5=0

On comparing it to ax + by + c = 0

a=-2, b=0, c =5

 

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Hope this will help you.....

Answered by TrapNation
229
Hey I'm MrMysterious

The Answer of your Question is ->


(i) 2x + 3y = 9.35
⇒ 2x + 3y - 9.35 = 0
On comparing this equation with ax + by + c = 0, we get
a = 2x, b = 3 and c = -9.35

(ii) x - y/5 - 10 = 0
On comparing this equation with ax + by + c = 0, we get
a = 1, b = -1/5 and c = -10


(iii) -2x + 3y = 6
⇒ -2x + 3y - 6 = 0
On comparing this equation with ax + by + c = 0, we get
a = -2, b = 3 and c = -6

(iv) x = 3y
⇒ x - 3y = 0
On comparing this equation with ax + by + c = 0, we get
a = 1, b = -3 and c = 0

(v) 2x = -5y
⇒ 2x + 5y = 0
On comparing this equation with ax + by + c = 0, we get
a = 2, b = 5 and c = 0

(vi) 3x + 2 = 0
⇒ 3x + 0y + 2 = 0
On comparing this equation with ax + by + c = 0, we get
a = 3, b = 0 and c = 2

(vii) y - 2 = 0
⇒ 0x + y - 2 = 0
On comparing this equation with ax + by + c = 0, we get
a = 0, b = 1 and c = -2

(viii) 5 = 2x
⇒ -2x + 0y + 5 = 0
On comparing this equation with ax + by + c = 0, we get
a = -2, b = 0 and c = 5

✴Brainly benefactor✴
From MrMysterious
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