Question

Question 2
Find the values of a, b and c​

Answer 1

Answer:

a+55+60=180

a+115=180

a=180-115

a= 65°

a+b=180°

65+b=180°

b=180-65

b=115°

b+c+40=180

115+40+c=180

c= 180-155

c= 25°

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Answer 2

Answer:

C=125°,A=70°,B=110°

Step-by-step explanation:

value of c

55° + C =180° (linear pair)

C = 180-55

C = 125°

VALUE OF A

SUM OF INTERIOR ANGLES OF A TRIANGLE EQUALS TO 180°

THEREFORE SUM OF TRIANGLE PQA=180°

P + Q + A = 180°

55°+60°+ A=180°

A+110°=180°

A=180°-110°

A=70°

VALUE OF B

A + B = 180° (A and B forms linear pair)

70°+B =180°

B=180°-70°

B=110°

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