Question

Question 2: If Sin A = 3/4, Calculate cos A and tan A​

Answer 1

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Let, Side opposite to angle θ = BC =3k and Hypotenuse = AC =4k where, k is any positive integer So, by Pythagoras theorem, we can find the third side of a triangle ⇒ (AB)2 + (BC)2 = (AC)2 ⇒ (AB)2 + (3k)2 = (4k)2 ⇒ (AB)2 + 9k2 = 16k2 ⇒ (AB)2 = 16 k2 – 9 k2 ⇒ (AB)2 = 7 k2 ⇒ AB =k√7 So, AB = k√7

Answer 2

What is this, Sorry I can't understand this