QUESTION :
2 men and 3 boys together can do a piece of work in 8 days. The same work is done in 6 days by 3 men and 2 boys together.
How long would 1 boy alone or 1 man alone take to complete the work??
PLEASE ANS ASAP..!!!
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Answered by
0
Let 1 boy alone can do a piece of work in x days and 1 man alone can do a piece of work in y days.
So, 1 day work of 1 boy =
x
1
and 1 day work of 1 man =
y
1
ATP
x
3
+
y
2
=
8
1
.........(i)
and
x
2
+
y
3
=
6
1
.......(ii)
Multiplying equation (i) by 2 and equation (ii) by 3
x
6
+
y
4
=
4
1
x
6
+
y
9
=
2
1
------------------------------------------
−
y
5
=−
4
1
⇒ y=20
substitute y=20 in equation (i)
x
3
+
20
3
=
8
1
x
3
=
8
1
−
10
1
x
3
=
40
5−4
x
3
=
40
1
⇒ x=120
So, one boy alone can do a piece of work in 120 days
and one man alone can do a piece of work in 20 days.
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0
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