"Question 2 Mrs. Kaushik has a square plot with the measurement as shown in the following figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs 55 per m2.
Class 8 Mensuration Page 171"
Answers
Mensuration:
Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.
Plane Figure: A figure which lies in a plane is called a plane figure.
For e.g: a rectangle, square, a rhombus, a parallelogram, a trapezium.
Perimeter:
The perimeter of a closed plane figure is the total length of its boundary.
In case of a triangle or a polygon the perimeter is the sum of the length of its sides.
Unit of perimeter is a centimetre (cm), metre(m) kilometre(km) e.t.c
Area: The area of the plane figure is the measure of the surface enclose by its boundary.
The area of a triangle are a polygon is the measure of the surface enclosed by its sides.
A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.
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Solution:
Answer is in the attachment..
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Hope this will help you...
Given:
- Side of a square plot = 25 m
- Length of the house = 20 m
- Breadth of the house = 15 m
To Find:
The total cost of developing a garden around the house at the rate of Rs 55 per .
Formula:
Area of a square plot = square of a side =
Solution:
Side of a square plot = 25 m
Area of a square plot = square of a side =
Therefore, area of a square plot is
Breadth of the house = 15 m
∴ Area of a square = Length × Breadth
Area of a garden = Area of a square plot - Area of a house
∵ Cost of developing the garden per sq. m
∴ Cost of developing the garden 325 sq. m = Rs. 55 × 325
Hence,
Cost of developing a garden is Rs. 17,875