Question

Question 2 Reduce the following equations into intercept form and find their intercepts on the axes.

(i) 3x + 2y – 12 = 0

(ii) 4x – 3y = 6

(iii) 3y + 2 = 0.

Class X1 - Maths -Straight Lines Page 227

Answer 1

(a) 3x + 2y - 12 = 0
3x + 2y = 12
3x/12 + 2y/12 = 12/12
x/4 + y/6 = 1
compare with x/a + y/b = 1
a = 4, b = 6
so, x-intercept = 4
y-intercept = 6


(b) 4x - 3y = 6
4x/6 - 3y/6 = 6/6
x/(6/4) -y/2 = 1
x/(3/2) + y/(-2) = 1
compare with x/a + y/b = 1
a = 3/2 , b = -2
so, x-intercept= 3/2
y-intercept = -2


(c) 3y +2 = 0
3y + 0.x = -2
3y/-2 + 0.x/-2 = -2/-2
y/(-2/3) + x/(-2/0) = 1
y/(-2/3) + x/∞ = 1
hence,
Y-intercept = (-2/3)
and no intercept on x-axis.