Question 2 .
Thanks in advance
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20√3 km/h is the right answer
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As diagram is not possible for me to draw I am explaining without it
By resolving vertical and horizontal component of velocity
Vcos30=v and Vsin30=20
So, by using Vsin30=20
V×1/2=20 =V=40
By putting V=40 in Vcos30=v
So, we get v=40cos30=20√3km/hr.
I HOPE THIS WIL L HELP U.
By resolving vertical and horizontal component of velocity
Vcos30=v and Vsin30=20
So, by using Vsin30=20
V×1/2=20 =V=40
By putting V=40 in Vcos30=v
So, we get v=40cos30=20√3km/hr.
I HOPE THIS WIL L HELP U.
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