Math, asked by muralisadananda, 3 months ago

Question 2
Using Factor theorem factorise 2x3+19x2+38x+21

Answers

Answered by Salmonpanna2022
5

Step-by-step explanation:</p><p>\huge\underline{ \mathfrak{ \red{Given}}} </p><p> \sf \: factorise \: 2x^3+19x^2+38x+21factorise2x3+19x2+38x+21</p><p></p><p>\huge \underline{ \mathfrak{ \red{to \: find}}} </p><p></p><p>\mathfrak{ \orange{simplyfy \: the \: \: given \: \: factory}}simplyfythegivenfactory</p><p> \huge \underline{ \mathfrak{ \red{solution}}} : -solution:−</p><p> \\ \begin{gathered} \sf \to \: 2x^3 + 19x^2+ 38x + 21 \\ \\ \sf \to \: {x}^{2} ( {x}^{2} + x) + 38x + 21 \\ \\ \sf \to \: x\:( x+ x) {x}^{2} + 38x + 21 \\ \\ \sf \to \: \:(x + x)x(x + 38) + 21 \\ \\ \sf \to \red{(x + x) ( x + 21)(x + 38) }\\ \\ \\ \end{gathered}→2x3+19x2+38x+21→x2(x2+x)+38x+21→x(x+x)x2+38x+21→(x+x)x(x+38)+21→(x+x)(x+21)(x+38) \\

Similar questions