Question

"Question 2 Write a Pythagorean triplet whose one member is (i) 6 (ii) 14 (iii) 16 (iv) 18

Class 8 Squares and Square Roots Page 98"

Answer 1

Pythagorean triplets:

For any natural number m > 1, we have (2m) ² + (m2 – 1)²= (m2 + 1)² . So, 2m, m² – 1 and m² + 1 forms a Pythagorean triplet.

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Solution:

i)

Let  2m = 6
 m = 3

m²+ 1 = 3² + 1= 9 + 1 = 10

m²- 1 = 3 2 - 1 = 9 - 1 = 8

check:

6 ² + 8² = 36 + 64 = 100 = 10²

Hence, the triplet is 6, 8 & 10 

ii)

Let  2 m = 14

 m = 7

 m² + 1 = 7²+ 1 = 49 + 1 = 50

m²- 1 = 7² - 1 = 49 - 1 = 48

check:

14² + 48² = 196 + 1304 = 2500 = 50²

Hence, the triplet is 14, 48, and 50 

iii)

Let 2 m = 16,

 m = 8

 m² + 1 = 8² + 1 = 64 + 1 = 65

m²- 1 = 8 2 - 1 = 64 - 1 = 63

check:

16² + 63² = 256 + 3969 = 4225 = 65²

Hence, the triplet is 16, 63 & 65 

 

iv)

Let  2 m = 18
 
m = 9

m² + 1 = 9² + 1 = 81 + 1 = 82

 m² - 1 = 9² - 1 = 81 - 1 = 80

check:
18²+ 80² = 324 + 6400 = 6724 = 82²

Hence, the triplet is 18, 80 & 82 

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Hope this will help you....

Answer 2

Answer:

Which of the following is a Pythagorean triplet? (a) (2, 3, 5) (b) (5, 7, 9) (c) (6, 9, 11) (d) ((8, 15, 17

Step-by-step explanation:

Which of the following is a Pythagorean triplet? (a) (2, 3, 5) (b) (5, 7, 9) (c) (6, 9, 11) (d) ((8, 15, 17