Question 2.
(x² + 2x - 15 ) is a factor of x + ax + bx - 30. Find the values of 'a and bº
Question 3.
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Solution :
Let p(x)=x3+ax2−bx−30
Given p(x) is exactly divisible by x2−2x−15,i.e, (x−5)(x+3)
⇒p(x) is divisible by (x+3)and(x−5)
∴p(−3)=0andp(5)=0
consider p(−3)=0
⇒(−3)3+a(−3)2−b(−3)−30=0
⇒−27+9a+3b−30=0
⇒9a+3b−57=0
⇒3a+b−19=0 (1)
Now , consider p(5)=0
That is , 53+a(5)2−b(5)−30=0
⇒125+25a−5b−30=0
⇒25a−5b+95=0
⇒5a−b+19=0 (2)
Adding Eqs . (1)and (2) , we get
8a=0
⇒a=0
Subsrtituting a in Eq . (1) . we get b = 19.
∴ The required values of a and b are 0 and 19 respectively.
⇒p(x)=x3+0(x2)−19x−30.
That is , p(x)=x3−19x−30.
Thus , the third factor is x+2.
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