Question

Question 20
4 points
0.24 9 of tribasic acid require 100 ml of 0.1 M
NaOH solution for neutralisation. What is the
molecular mass of acid?​

Answer 1

0.1 L x 0.1 M/ L x 40 grams /mole = 0.4 grams of NaOH. MW =( 120 x 0.24 ) / 0.24 = 72.

Answer 2

Answer:

0.1 L x 0.1 M/ L x 40 grams /mole = 0.4 grams of NaOH. MW =( 120 x 0.24 ) / 0.24 = 72.