Question

QUESTION 20:
A charge of 5c experiences a force of 5000 N when it is kept in a uniform electric field. What is the potential difference between two points
separated by a distance of 1 cm​

Answer 1

Answer:

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Answer 2

Answer:Charge= 5C

Force= 5000N

Distance= 0.01m

V=?

t= Force/q

=5000/5

​

=1000V

also, E= dr/dv

​

⇒dv=E(dr)=1000 {100/(0.01)}m

v=10V