Question

QUESTION 20:
An object in projected up the inclined at the angle shown in the figure with an initial velocity of 30m/s .The
distance x up the incline at which the object lands is ?​

Answer 1

Step-by-step explanation:

Given An object in projected up the inclined at the angle shown in the figure with an initial velocity of 30 m/s .The  distance x up the incline at which the object lands is ?​

• We need to find the distance.
• Given two angles are 30 degree and 30 degree angles and another angle 60 degree in the figure.
• So we have g sin 30 and g cos 30
• So using equation of motion S = ut + 1/2 at^2 we get
•                                               So x = 30 cos 30 t + 1/2 (- g sin 30) t^2  
• So time of flight will be 2usin theta / g
• So we will use equation of motion for incline to be perpendicular.So the displacement is 0.
• So 0 = ut + 1/2 at^2
•       = 30 sin 30 + 1/2 (- g cos 30) t^2
•  So t = 60 sin 30 / 10 cos 30
• So t = 6 x 1/2  / √3 / 2
•       = 3 x 2 / √3
• So t = 2√3
• Now we need to substitute the value of t in the above equation.
• So x = 30 x √3 / 2 x 2√3 + 1/2 (- 5) (12)
• Or x = 90 – 30
• Or x = 60 m

Reference link will be

https://brainly.in/question/1392343

Answer 2

Answer:

Step-by-step explanation:

Given An object in projected up the inclined at the angle shown in the figure with an initial velocity of 30 m/s .The  distance x up the incline at which the object lands is ?​

We need to find the distance.

Given two angles are 30 degree and 30 degree angles and another angle 60 degree in the figure.

So we have g sin 30 and g cos 30

So using equation of motion S = ut + 1/2 at^2 we get

                                             So x = 30 cos 30 t + 1/2 (- g sin 30) t^2  

So time of flight will be 2usin theta / g

So we will use equation of motion for incline to be perpendicular.So the displacement is 0.

So 0 = ut + 1/2 at^2

     = 30 sin 30 + 1/2 (- g cos 30) t^2

So t = 60 sin 30 / 10 cos 30

So t = 6 x 1/2  / √3 / 2

     = 3 x 2 / √3

So t = 2√3

Now we need to substitute the value of t in the above equation.

So x = 30 x √3 / 2 x 2√3 + 1/2 (- 5) (12)

Or x = 90 – 30

Or x = 60 m

Reference link will be

Step-by-step explanation: