Question

|⭕+QUESTION+⭕|

200cm³ of an aqueous solution of a protein contains 1.26g of the protein. The oamotic pressure of such a solution at 300k is found to be 2.57×10^-3 bar. calculate the molar mass of the protein.​

Answer 1

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Answer 2

HERE YOUR ANSWER:

The various quantities known to us are as follows:

π = 2.57×10^-3 bar.

V = 200 cm³ = 0.200 litre

T = 300 K

R = 0.083 L bar/mol K

so, here

$m_{2} = \frac{1.26g \times 0.083 \: l \: bar {k}^{ - 1} {mol}^{ - 1} \times 300k }{2.57 \times {10}^{ - 3}bar \times 0.200 \: l } \\ \\ = 61</strong><strong>,</strong><strong>022g \: {mol}^{ - 1}$

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