Question

Question 21, 22 and 25

Answer 1

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let the length of the shortest side be :- X

so, the longest side is =3 times the shortest side
= 3 x

and length of the third side=(3x-2)cm

NOW:-

Perimeter = Sum of three sides
=X + 3X + (3X-2)
=X + 3X +3X-2
=7X-2

Given that,

Perimeter of the triangle is atleast 61 cm,

I.e,
$perimeter \geqslant 61$

$7x - 2 \geqslant 61$
$7x \geqslant 61 + 2$
$7x \geqslant 63$
$x = 63\div 7$
$x \geqslant 9$
Minimum value of X is 9.....

HENCE , FOUND...

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Answer 2

ĀNSWĒR ✍☺

Let the shorter side = xcm

Longest = 3 x cm

Third side = 3x - 3 cm

Now,

According to question

$x + 3x + 3x - 2 \geqslant 61 \\ = 7x - 2 \geqslant 61 \\ = 7x \geqslant 61 + 2 \\ = 7x \geqslant 63 \\ \\ divide \: both \: sides \: \: by \: 7 \\ \frac{7x}{7} \geqslant \frac{63}{7} \\ = x \geqslant 9cm \\ minimum \: length \: of \: shorter \: side = 9cm$

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#Nishu HarYanvi ❤