Question 21
Multi Select Type
If 100mL of 1M H, SO, solution is mixed with 100ml of 9.8% (w/w) of H, so, solution (d=1g/ml) then
concentration of solution remains same
Volume of solution becomes 200ml
mass of H, so, in the solution is 98gm
mass of H. so, in the solution is 19.6gm
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Answers
Answered by
0
Explanation:
Correct option is
B
volume of solution becomes 200 ml.
D
mass of H
2
SO
4
in the solution is 19.6 g.
100 mL of 1 M H
2
SO
4
+100mL (98%, d=0.1)H
2
SO
4
=100×1M+100mL×(
98
98×10×0.1
)
=100×1M+100×1M
∴[H
2
SO
4
]=
200mL
100×1+100×1
=1M=98g/1000mL
Mass of H
2
SO
4
=
1000mL
98g×200mL
=19.6g
Concentration of each component becomes half of the initial value.
Hence, options B and D are correct.
Answered by
0
Explanation:
100 mL of 1 M H
2
SO
4
+100mL (98%, d=0.1)H
2
SO
4
=100×1M+100mL×(
98
98×10×0.1
)
=100×1M+100×1M
∴[H
2
SO
4
]=
200mL
100×1+100×1
=1M=98g/1000mL
Mass of H
2
SO
4
=
1000mL
98g×200mL
=19.6g
Concentration of each component becomes half of the initial value.
Hence, options B and D are correct.
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