Question

Question 21
Multi Select Type
If 100mL of 1M H, SO, solution is mixed with 100ml of 9.8% (w/w) of H, so, solution (d=1g/ml) then
concentration of solution remains same
Volume of solution becomes 200ml
mass of H, so, in the solution is 98gm
mass of H. so, in the solution is 19.6gm
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Answer 1

Explanation:

Correct option is

B

volume of solution becomes 200 ml.

D

mass of H

2

SO

4

in the solution is 19.6 g.

100 mL of 1 M H

2

SO

4

+100mL (98%, d=0.1)H

2

SO

4

=100×1M+100mL×(

98

98×10×0.1

)

=100×1M+100×1M

∴[H

2

SO

4

]=

200mL

100×1+100×1

=1M=98g/1000mL

Mass of H

2

SO

4

=

1000mL

98g×200mL

=19.6g

Concentration of each component becomes half of the initial value.

Hence, options B and D are correct.

Answer 2

Explanation:

100 mL of 1 M H

2

SO

4

+100mL (98%, d=0.1)H

2

SO

4

=100×1M+100mL×(

98

98×10×0.1

)

=100×1M+100×1M

∴[H

2

SO

4

]=

200mL

100×1+100×1

=1M=98g/1000mL

Mass of H

2

SO

4

=

1000mL

98g×200mL

=19.6g

Concentration of each component becomes half of the initial value.

Hence, options B and D are correct.