Question

Question 22:
An electric heater which is connected to a 220 V supply line has two resistance coils A and B of 24 Ω resistance each. These coils can be used separately (one at a time), in series or in parallel. Calculate the current drawn when :
(a) only one coil A is used.
(b) coils A and B are used in series.
(c) coils A and B are used in parallel.

Lakhmir Singh Physics Class 10

Answer 1

Answer:

a) 9.16amp

b) 4.58 amp

c) 18.33 amp

Explanation:

An electric heater is connected to a supply line that has a voltage of 220V.

This supply line has two resistance coils A and B.

Resistance of A is 24ohm and B is also 24ohm.

So, we can conclude that resistance of A and B are equal.

Now, we know that the amount of voltage passed = amount of current drawn × Resistance.

V=IR

a) So, the amount of current drawn when A coil is used is : I= V/R

I= 220/24

I= 9.16 amp

b) When coil A and B are being used in series the amount of current drawn is : 220/48[ Since A+B = 24+24=48]

Therefore I = 4.58 amp

c) When coil A and B are in parallel series, total resistance would be 1/24 + 1/24 = 2/24

= 1/12

Therefore amount of current drawn is : 220/12 = 18.33amp

Therefore I = 18.33 amp

Answer 2

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