Question

Question 22: Convert the following SOP expression to an equivalent POS expression. ABC+AB'C' + AB'C+ABC'+A'B'C

A. (A'+B'+C')(A'+ B + C')(A'+B+C)
B. (A + B + C)(A + B'+ C)(A + B'+C')
C. (A'+B'+C')(A + B'+ C)(A + B'+ C)
D. (A + B + C)(A'+ B +C')(A + B'+C) ​

Answer 1

Answer:

I think..

(C)

hope it helps.

Answer 2

The SOP the expression to an equivalent POS B.(A + B + C)(A + B'+ C)(A + B'+C')

Explanation:

Min terms are= $7,4,5,6,1$

Hence corresponding maxterms will be $0,2,3$

SOP EQUIVALENT  POS:

• To convert the SOP function F = ∑ a, b, c (0, 2, 3, 5, 7) = a' b' c' + c b' c' + a b' c + abc' + abc into POS: In the first step, we change the operational sign to $\pi$.

• We find the missing indexes of the terms,$001, 110, and 100$.