Question 24 please help me
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Solution
SinA=1/3x
tanA=x/3
now....
cosA=(1/3x)/(x/3)=1/x²
secA=x²
therefore....
x²-1/x²=secA-cosA=
=1-cos²A/cosA
=sin²A/cosA
=tanAsinA
Answered by
2
Step-by-step explanation:
SinA=1/3x
tanA=x/3
now....
cosA=(1/3x)/(x/3)=1/x²
secA=x²
therefore....
x²-1/x²=secA-cosA=
- =1-cos²A/cosA
=sin²A/cosA
=tanAsinA
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