Question

Question 26
In which of the following arrangement distance between two nearest
neighbours is maximum considering identical atoms in all
arrangements
(1) Simple cubic
(2) bcc
(3) fcc
(4) equal in all

Answer 1

option a is correct simple cubic is answer

Answer 2

The distance between two nearest  neighbours is maximum in:

(1) Simple Cubic Arrangement

- The distance between two neighbour atoms in the distance between their centres.

- In simple cubic lattice, atoms are present only at corners.

- So, the distance between their centres is the edge length 'a' which is the maximum.

- In BCC, one atom is present at the body centre.

- So, the distance between two neighbouring centres is half of the body diagonal, i.e. '√3a/2'.

- In FCC, atoms are also present at the face centres.

- So, the distance between two neighbouring centres is half of the face diagonal, i.e. 'a/√2'.