Question

Question # 27 Find the sum of first 50 terms of the given sequence; 4, 9, 14, 19, 24, ...​

Answer 1

Answer:

4+(50-1)×5=249 is the required solution

Answer 2

Answer: 6325

Given: 4, 9, 14, 19, 24, ...​

To Find: The sum of the first $50$ terms of the given sequence.

Explanation:

Here, the series is $4, 9, 14, 19, 24, ...$

$a_{1} =4$ and $d=5$

We need to determine the sum of the first $50$ terms of the given sequence.

So, $n=50$

We know $s_{n}=\frac{n}{2}\left(2 a_{1}+(n-1) d\right)$.

When substituting the known values, we get

$S_{50} =\frac{50}{2}(2(4)+(50-1) 5)$

$=25(8+(49) 5)$

$=25(8+245)$

$=25(253)$

$=6325$

Therefore, the sum of the first $50$ terms of the given sequence is $6325$.

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