Chemistry, asked by yashswastik55, 3 days ago

Question 29: Two gases He and Ne at 127°C and 27°c, calculate the ratio of the de Broglie's wave length for Ne to He gases is 1. 1: 1.94 2. 1: 3.43 3. 1: 4.141 4. 1: 8.987​

Answers

Answered by MichhDramebaz
1

Answer:

Polynomials are algebraic expressions that consist of variables and coefficients. ... We can perform arithmetic operations such as addition, subtraction, multiplication and also positive integer exponents for polynomial expressions but not division by variable. An example of a polynomial with one variable is x2+x-12

Answered by hamshitham30
0

Correct option is

D

3

8

de-Broglie wavelength λ=

mv

h

Where the speed (r.m.s) of a gas particle at the given temperature (T) is given as

2

1

mv

2

=

2

3

kT

⇒v=

m

3KT

where k= Boltzmanns constant and m= mass of the gas particle and T= temperature of the gas in k

⇒mv=

3mKT

⇒λ=

mv

h

=

3mkT

h

λ

He

λ

H

=

m

H

T

H

m

He

T

He

=

(2 amu) (273+127)

k

(4 amu) (273+127)

k

=

3

8

Hence (D) is correct.

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